can a sustained have charge of 6.0 into 10 to the power minut 18 coulom
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Answer:
Q=6.0×10
−8
C
Potential at distance x=3 m V
1
=
x
KQ
=
3
9×10
9
×6×10
−8
=180 V
Potential at distance x=6 m V
2
=
x
KQ
=
6
9×10
9
×6×10
−8
=90 V
Charge of electron e=−1.6×10
−19
C
Work done W=e(V
2
−V
1
)=−1.6×10
−19
(90−180)=1.44×10
−17
J
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