can an one factorise x^6+8b^3
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Factorise x^6 + 8b³
a³ + b³ = (a + b)(a² + b² - ab)
==> (x²)³ + (2b)³
==> (x² + 2b){(x²)² + (2b)² - x²*2b}
==> (x² + 2b)(x⁴ + 4b² - 2bx²)
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