Math, asked by devilkiller2, 11 months ago

can an one factorise x^6+8b^3

Answers

Answered by Arceus02
4

\mathtt{\large{\red{\underline{Question:-}}}}

Factorise x^6 + 8b³

\mathtt{\large{\red{\underline{Formula\:used:-}}}}

a³ + b³ = (a + b)(a² + b² - ab)

\mathtt{\large{\red{\underline{Answer:-}}}}

==> (x²)³ + (2b)³

==> (x² + 2b){(x²)² + (2b)² - x²*2b}

==> (x² + 2b)(x⁴ + 4b² - 2bx²)

Answered by ritvik86
0

Step-by-step explanation:

its yur solution dear...

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