Can anboby solve this question?
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According to principle of calorimetry
m1c1(t1-t)=m1c1(t-t2)
Here
m1=0.2kg
m2=0.8kg
c1=?
c1=4200 J/Kg °C
t1=100°C
t2=20 °C
t=20°C
Substituting
0.2xc1x80=0.8x4200x0
So
Most probably the value of c1 would be 0
m1c1(t1-t)=m1c1(t-t2)
Here
m1=0.2kg
m2=0.8kg
c1=?
c1=4200 J/Kg °C
t1=100°C
t2=20 °C
t=20°C
Substituting
0.2xc1x80=0.8x4200x0
So
Most probably the value of c1 would be 0
Dårviñ714:
Is it correct???
I don't know
But I also got the same answer
Where did you find this question?
text book
Which publishers?
Arihant
I think it is the correct answer
yes
I also
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