Question

can any 1 help me in solving this...?

Answer 1

angle LMB=88(corresponding angles)
angle LMB+ angle LMQ =180(linear pair)
88+ ANGLE LMQ=180
ANGLE LMQ =180-88
angle LMQ = 92
ANGLE LMQ + X = 110(exterior angle property)
92 + x =110
x =110-92
x= 18

Answer 2

Answer: Angle LMB=AngleB=88° (corresponding angles)
QB is a line,
AngleLMB+AngleLMQ=180°(Linear pair)
88° + Angle LMD= 180
Angle LMD =180°-88°
Angle LMQ=92°
Now, DC is a line
AngleCLQ +AngleMLQ=180°(Linear pair )
110° + Angle MLQ= 180°
Angle MLQ=180° -110°
=70°
In triangle MLQ,
AngleLMQ +Angle MLQ+x =180°(Angle sum property of triangle)
92°+70°+x=180°
162° +x= 180°
x=180°-162°
=18°
Therefore,x=18°