can any 1 solve this?
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Mass of water(m)=500 kg
Height(h)=60 m
g= 10 N/kg
a) W= F×S
=mg × h
=500×10×60
=5000×60
=300000 J
=3 × 10^5 J
b) U= mgh
=work done
=3 × 10^5 J
c) P=W/t
=300000/40
=75000 W
Assumption: Work Done is the Energy used
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