can any body solve this
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Remember this formula
Required equation will be :
x^2 - (sum of the roots)x + (Product of the roots) = 0
Now just put those roots as directed
Required equation will be :
x^2 - (sum of the roots)x + (Product of the roots) = 0
Now just put those roots as directed
snehaprabhu:
kk
i got it
Answered by
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Basically, the general equation when α,β are considered as roots is
x² - x(α+β) + αβ = 0
i) α = - 2 and β = -3
So, eqn is x² - x(-5) + 6 = 0
x² + 5x + 6 = 0
ii) α = 1/2 and β = -4
x² - x(-7/2) - 2 = 0
2x² + 7x - 4 =0
iii) α = -1/2 and β = 1/3
x² - x(-1/6) - 1/6 = 0
6x² + x - 1 = 0
iv) α = 2/3 and β = 3/2
x² - x(13/6) + 1 = 0
6x² - 13 x + 6 = 0
x² - x(α+β) + αβ = 0
i) α = - 2 and β = -3
So, eqn is x² - x(-5) + 6 = 0
x² + 5x + 6 = 0
ii) α = 1/2 and β = -4
x² - x(-7/2) - 2 = 0
2x² + 7x - 4 =0
iii) α = -1/2 and β = 1/3
x² - x(-1/6) - 1/6 = 0
6x² + x - 1 = 0
iv) α = 2/3 and β = 3/2
x² - x(13/6) + 1 = 0
6x² - 13 x + 6 = 0
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