Question

can any body solve this? ​

Answer 1

Answer:

what to solve? please send the full question, by the way -

Horizontal velocity = 2cos 30° = 2 × √3/2 = √3m/s

Vertical velocity = 2sin30° = 2 × 1/2 = 1m/s

Range (R) = u × t (where 'u' is the initial horizontal velocity and 't' is the time taken)

Highest point = u^2 / 2a ( where 'u' is initial vertical velocity and 'a' is acceleration due to gravity)