can any body solve this one ?
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tan(A+B)=tanA+tanB/(1-tanAtanB)
=n/(n+1) +1/(2n+1)/(1- n/(n+1)(1/(2n+1))
=2n²+n+n+1/(n+1)(2n+1)/(2n²+3n-n+1/(n+1)(2n+1)
2n²+2n+1/(2n²+2n+1)=1
tan(A+B)=1
A+B=tan-¹ (1)
=tan-¹ (tan45)
=45
A+B=45
LEAST positive value
=n/(n+1) +1/(2n+1)/(1- n/(n+1)(1/(2n+1))
=2n²+n+n+1/(n+1)(2n+1)/(2n²+3n-n+1/(n+1)(2n+1)
2n²+2n+1/(2n²+2n+1)=1
tan(A+B)=1
A+B=tan-¹ (1)
=tan-¹ (tan45)
=45
A+B=45
LEAST positive value
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