can any body solve this sum......solve the quadratic equation by factorisation method.....and can u guys explain me also......
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hope its help...
plss mark as a brainliest*
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Sid234:
sry 4 bad handwriting bro....fastly me solve kiya dts y....
it's okay
u did understand naa?
yaa
I understood
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By LCM it becomes
15*[x²+(x+1)²]=34x(x+1)
30x²+30x+15=34x²+34x
34x²-30x²+34x-30x-15=0
4x²+4x-15=0 ...........〈1〉
factors of -4*15=-2*2*3*5
+10x and -6x makes sum=4x and product=-60x²
So 〈1〉 can be written as
4x²+10x-6x-15=0
2x(2x+5)-3(2x+5)=0
(2x+5)(2x-3)=0
15*[x²+(x+1)²]=34x(x+1)
30x²+30x+15=34x²+34x
34x²-30x²+34x-30x-15=0
4x²+4x-15=0 ...........〈1〉
factors of -4*15=-2*2*3*5
+10x and -6x makes sum=4x and product=-60x²
So 〈1〉 can be written as
4x²+10x-6x-15=0
2x(2x+5)-3(2x+5)=0
(2x+5)(2x-3)=0
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