Math, asked by SoumyojitRoy1906, 1 month ago

Can any help me, with this question​

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Answers

Answered by BrainlyGovind
1

Given that,

l=20m

b=15m

d=4m (d-h)

We know that,

Area for coner its floor2d(l+b)+lb

=2(4)(20+15)+(20×15)

=8×35+300

=280+300

=580m

2

Rate of coner its floor Rs.12/m

2

∴ Total cost of coner its floor =580×12

Rs.6960

Then,

We get Rs.6960

hope it helps you

Answered by Anonymous
60

Answer:

{\large{\underline{\underline{\pmb{\sf{Given...}}}}}}

  • \leadsto Base of Parallelogram = 10 cm
  • \leadsto Altitude of Parallelogram = 3.5 cm

\begin{gathered}\end{gathered}

{\large{\pmb{\sf{\underline{\underline{To \: Find...}}}}}}

  • \leadsto Area of Parallelogram

\begin{gathered}\end{gathered}

{\large{\pmb{\sf{\underline{\underline{Using \: Formula...}}}}}}

{\dag{\underline{\boxed{\sf{Area \:  of  \: a  \: parallelogram = Base  \times  Altitude }}}}}

\begin{gathered}\end{gathered}

{\large{\pmb{\sf{\underline{\underline{Diagram...}}}}}}

\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(2,4)\qbezier(2,4)(1.6,4)(7,4)\qbezier(6,1)(6,1)(7,4)\qbezier(2,4)(2,4)(2,1)\qbezier(2,4)(1.6,4)(6.5,2.5)\put(0.7,0.5){\sf B}\put(6,0.5){\sf C}\put(1.8,4.3){\sf A}\put(7,4.3){\sf D}\put(2,0.5){\sf}\put(3.3,0.5){\sf 10 cm}\put(6.7,1.5){\sf }\put(6.8,2.4){\sf}\put(2.2,2.2){\sf 3.5 cm}\end{picture}

  • \leadsto See this diagram from website Brainly.in.
  • \leadsto Check out the given attachment also!

\begin{gathered}\end{gathered}

{\large{\pmb{\sf{\underline{\underline{Solution...}}}}}}

 \quad{: \longmapsto{\sf{Area \:  of  \: a  \: parallelogram = Base  \times  Altitude }}}

  • Substituting the values

\quad{: \longmapsto{\sf{Area \:  of  \: a  \: parallelogram = 10\times  3.5 }}}

\quad{: \longmapsto{\sf{Area \:  of  \: a  \: parallelogram = 10\times  \dfrac{35}{10} }}}

\quad{: \longmapsto{\sf{Area \:  of  \: a  \: parallelogram = \cancel{10}\times  \dfrac{35}{\cancel{10}}}}}

\quad{: \longmapsto{\sf{Area \:  of  \: a  \: parallelogram =35 \:  {cm}^{2}  }}}

\quad\dag\underline{\boxed{\sf{Area \:  of  \: a  \: parallelogram =35 \:  {cm}^{2}  }}}

{\therefore{\underline{\underline{\sf{\red{The \:  Area \:  of \:  Parallelogram is  \: 35 \:  {cm}^{2}}}}}}}

\begin{gathered}\end{gathered}

{\large{\pmb{\sf{\underline{\underline{Learn \: More...}}}}}}

\boxed{\begin {minipage}{9cm} \\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}

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