Can any kind person help me??
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Step-by-step explanation:
log
10
x−2+log
10
y=0
⇒log
10
(x−2)y=0
⇒(x−2)y=1
⇒xy=1+2y (equation 1)
x + y−2 = x+y
Squaring both side,
⇒x+(y−2)+2
x(y−2)
=(x+y)
⇒2
x(y−2)
=2
⇒
x(y−2)
=1
⇒x(y−2)=1
⇒xy=(1+2x) (equation 2)
From equation 1 and 2
(x=y)
Putting this in equation 1
x 2 =1+2x
(x 2 −2x−1)=0
x=1+ 2 ,1-2
y=1+ 2 ,1− 2
But x,y both should be greater than 2.
∴(x+y)=2+2 ✓2
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