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Hey,
In triangle AEB and CED,
AB=CD(given)
angle AEB =angle CED (vertically opposite angles)
angle EAB=angle ECD(aternate angles)
Therefore,
Triangle AEB is congruent to triangle CED. (A. A. S axiom of conruency)
Now, In triangle AED and triangle BEC,
AD=BC(given)
angle AED=angle BEC(vertically opposite angles)
angle EAD=angle BCE(aternate angles)
Therefore,
Triangle AED is congruent to triangle BEC(A.A.S axiom of conruency)
Hope this helps!!!!
Plz mark as brainlest.
In triangle AEB and CED,
AB=CD(given)
angle AEB =angle CED (vertically opposite angles)
angle EAB=angle ECD(aternate angles)
Therefore,
Triangle AEB is congruent to triangle CED. (A. A. S axiom of conruency)
Now, In triangle AED and triangle BEC,
AD=BC(given)
angle AED=angle BEC(vertically opposite angles)
angle EAD=angle BCE(aternate angles)
Therefore,
Triangle AED is congruent to triangle BEC(A.A.S axiom of conruency)
Hope this helps!!!!
Plz mark as brainlest.
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