Question

can any of you help me with this one?:)

Answer 1

$10 \div 100 \times 990 \\ 990 \div 10 = 99$
so he gains 99 on 1st jeans
and loses 99 on 2nd jeans

therefore Sp of 1st jeans = 990 +99 = 1089
SP of second jeans = 990 - 99 = 891

Answer 2

HERE IS YOUR ANSWER..⬇⬇

1.$\underline{SOLUTION}$ ➡

$Let ,\\ \\ C.P .\: of \:the \: 1st \: pent \: = Rs.x \\ \\ 10\% \: profit \: on \: C.P .\: \: Then \\ \\ S.P. \: of \: the \: 1st \: pent \: = Rs \: .(x + 10\% \: of \: x) \\ \\ = Rs.(x + \frac{10}{100} x) \\ \\ = Rs. \frac{110x}{100} \\ \\ \\ A.T.Q., \\ \\ \frac{110x}{100} = 990 \\ \\ = > 110x = 99000 \\ \\ = > x = \frac{99000}{110} \\ \\ = >x = 900 \\ \\ So \: ,cost \: price \: of \: the \: first \:pent \: = rs.900$

$Again, \\ \\ C.P .\: of \: the \: 2nd \: pent \: = Rs. \: y \\ \\ 10\% \: \: loss \: on \: C.P. \: \: Then, \\ \\ S.P. \: of \: the \: 2nd \: pent \: = Rs.(y - 10\% \: of \: y) \\ \\ = Rs.(y - \frac{10}{100} y) \\ \\ = Rs. \frac{90y}{100} \\ \\ \\ A.T.Q., \\ \\ \frac{90y}{100} = 990 \\ \\ = > 90y = 99000 \\ \\ = > y = \frac{99000}{90} \\ \\ = > y = 1100 \\ \\ So, \: cost \: price \: of \: the \: 2nd \: pent \: = Rs.1100$

$Now, \\ \\ Total \: cost \: price \: of \: the \: two \: pents \: = Rs.(900 + 1100) \\ \\ =Rs. 2000 \\ \\ Total \: \: selling \: price \: of \: the \: two \: pents \: = Rs.990 + 990 \\ \\ = Rs.1980 \\ \\ \\ Here ,\\ \\ Cost \: price \: > Selling \: price \: \\ \\ So \:, \: there \: is \: a \: loss \\ \\ Loss \: = Cost \: price \: - Selling \: price \\ \\ =Rs. (2000 - 1980) \\ \\ = Rs.20 \\ \\ \\loss \: percent \: = \frac{loss}{cost \: price} \times 100 \\ \\ = \frac{20}{2000} \times 100 \\ \\ = 1\%$

$\underline{ANSWER}$ ➡ Loss 1 %

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