can any one ans plz 6
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at first show that the triangles ABE and triangle ACF are congurent,(through the parallelogram ABCA and ABCF.
once if the triangles are congurent the areas are equal
once if the triangles are congurent the areas are equal
khader3:
welcome
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hey here is ur answer
in ΔABC and ΔABE we have:-
ang. CAB=ang. EBA
ang. EAB= ang.ABC
BETWEEN SAME PARELLES
SO ΔABC=ΔEBA
and in ΔFCA and BAC we have:-
FAC =ACB
BAC=ACF
SOΔFCA=ΔBAC
BETWEEN SAME PARELLELS
SO BOTH ARE EQUALTO ΔABC
BOTH ARE EQUAL TO EACH OTHER
SO Δ ABE=ΔACF
HOPE IT HELPS
in ΔABC and ΔABE we have:-
ang. CAB=ang. EBA
ang. EAB= ang.ABC
BETWEEN SAME PARELLES
SO ΔABC=ΔEBA
and in ΔFCA and BAC we have:-
FAC =ACB
BAC=ACF
SOΔFCA=ΔBAC
BETWEEN SAME PARELLELS
SO BOTH ARE EQUALTO ΔABC
BOTH ARE EQUAL TO EACH OTHER
SO Δ ABE=ΔACF
HOPE IT HELPS
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