Math, asked by mohammedfaizan258, 11 months ago

can any one answer me the second on of polynomial.plz

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Answered by sahuraj457
0
for infinite number of solutions
 \frac{a1}{a2}  =  \frac{b1}{b2}  =  \frac{c1}{c2}  \\  \frac{k}{16}  =  \frac{4}{k}  =  \frac{k - 4}{k}  \\   {k}^{2}   = 64 \\ k =   +  - 8   \:  \:  - (1) \\  \frac{4}{k}  =  \frac{k - 4}{k}  \\ 4k =  {k}^{2}  - 4k \\ 8k =  {k }^{2}  \\ k = 0 \: and \: 8  \:  \:  - (2) \\ from \: (1) \: and \: (2) \:  \\ k = 8
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