Question

can any one answer this it's urgent please


In ∆PQR,if PQ>pR and bisectors of angle Q and angle R intersect at S. show that SQ >SR.​

Answer 1

Answer:

In △PQR,PQ>PR

⇒∠PRQ>∠PQR(Angle opposite to longer side is greater)

⇒

2

1

∠PRQ>

2

1

∠PQR

⇒∠SRQ>∠SQR since RS and QS are the bisectors of ∠PRQ and ∠PQR

In △SQR,∠SRQ>∠SQR

⇒SQ>SR since side opposite to greater angle is longer.