Question

Can any one answer this urgently please

The percentage of nitrogen in magnesium nitride is

a) 14 b) 28 c) 42 d) 56

Can any one know answer for this question ​

Answer 1

Answer:

Approx.

28

%

Explanation:

For

M

g

3

N

2

.

%

N

=

mass of nitrogen

molar mass of magnesium nitride

×

100

%

=

2

×

14.01

⋅

g

⋅

m

o

l

−

1

100.95

⋅

g

⋅

m

o

l

−

1

×

100

%

=

27.8

%

Answer 2

Answer:

b. 28

Explanation:

For Mg3N2. %

N=mass of nitrogen/molar mass of magnesium nitride×100%

=2×14.01⋅g⋅$mol^-1$/100.95⋅g$mol^-1$.×100%=27.8% = 28%%(approx.)