can any one explain me completing square mathod
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dishantsinghom:
i also want to know
i also dont know parso paper h or mughe abhi tak nahi aata
same here
hmmm...
Answers
Answered by
3
Completing The Square Method,
let us consider the below equation
2x²-5x+3=0
first step is to make the co efficient 1
divide both the sides by 2
now We have
x²-(5/2)x+3/2=0
Now send the third term without x one, on RHS side=
x²-(5/2)x=-3/2
now the most important step multiply the second term of LHS by 1/2 and add the square of the product on both sides. now the LHS becomes an identity. so you have both LHS in square
Send the square on RHS thus it will become a root on RHS and since it's a quadratic equation you'll get two answers
Hope this helps
let us consider the below equation
2x²-5x+3=0
first step is to make the co efficient 1
divide both the sides by 2
now We have
x²-(5/2)x+3/2=0
Now send the third term without x one, on RHS side=
x²-(5/2)x=-3/2
now the most important step multiply the second term of LHS by 1/2 and add the square of the product on both sides. now the LHS becomes an identity. so you have both LHS in square
Send the square on RHS thus it will become a root on RHS and since it's a quadratic equation you'll get two answers
Hope this helps
iska matlab hume important step ko pehle 5 bana parega or uske bad dono sides me 5 ka square yani 25 ko add krna parega ❓❓
nahi 5/2 ko 1/2 multiple karna hai or uske baad uska square karke dono side add karna hai
yani 5/2 ko 5/4 bana kr use 25/16 krna h ❓❓
ha
ohk thanks
u made it easier to me
it was a big task to understand it
thanks a lot
welcome
°_°
Answered by
6
completing the square method...
sabse pehle u have to make the constant of first number 1.
for that divide each no. with the first constant no.
now take the 3rd no. to RHS side.
ab jo second no. hai uske constant me 1 upon 2 multiply karo and add it to LHS and RHS (don't take the variable)
u will see that the LHS will be in the form of (a+b)^2 or (a-b) ^2
combine the identity and solve the equation...
u will get the value of x.
hope it helped... kuch samajh na aaya ho to ask in the comments section...
sabse pehle u have to make the constant of first number 1.
for that divide each no. with the first constant no.
now take the 3rd no. to RHS side.
ab jo second no. hai uske constant me 1 upon 2 multiply karo and add it to LHS and RHS (don't take the variable)
u will see that the LHS will be in the form of (a+b)^2 or (a-b) ^2
combine the identity and solve the equation...
u will get the value of x.
hope it helped... kuch samajh na aaya ho to ask in the comments section...
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