Question

can any one send me please ​

Answer 1

EXPLANATION:-

GIVEN:-

$\sf\;pole\;in\;mud=\frac{1}{8}\;of\;pole\\\\pole\;in\;water=\frac{2}{8}\;of\;pole$

STEP BY STEP EXPLANATION:-

Total length of pool=72 m

$\sf\;pole\;in\;mud=\frac{1}{8}\times72\\\\==>9\;m$

$\sf\;pole\;in\;water=\frac{1}{3}\times72\\\\==>24\;m$

Total pole under water and mud=24+9

==>33 m

Pole above water=Total length of pool - Tole under water and mud

Pole above water=72-33

Pole above water=39 m

Hence 39 metre of pool is above water .

Answer 2

Answer:

Simple.

Let the total length be ‘L'.

The length in air is L-(L/2 + L/3).

This gives us the length in air is L/6.

But it is given that length in air is 20 dm

So 20 dm= L/6

Therefore L is 120 dm. That is 12 metres.

Step-by-step explanation:

this is your answer.