Question

can any one solve it for me . pls
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Answer 1

Given :--

• AB is the Diameter .
• Angle CBA = 48°

To Find :-

• Angle CAB = ?

Concept Used :-

• A triangle drawn from two ends of a diameter of a circle makes an angle of 90° at the circumference.
• Angle sum Property.

Solution :-

As it is given that, AB is the diameter of the circle .. So, From above Told concept we can say That :-

→ Angle ACB = 90°.

Now, By Angle Sum property we know that, Sum of all Three angles of a ∆ is 180°..

So,

→ Angle CAB + Angle CBA + Angle ACB = 180°

Putting values now,

→ Angle CAB + 48° + 90° = 180°

→ Angle CAB = 180- (48+90)

→ Angle CAB = 180° - 138°

→ Angle CAB = 42°...

Hence , Angle CAB will be 42°..

Answer 2

Step-by-step explanation:

$\huge\underline\purple{\sf Answer :-}$ In triangle ∆ACB

$\large\implies{\sf }$ Angle ABC= 48° (Given)

• Angle ACB = 90° ( Right angled triangle) (Given)

Now, By the angle sum property of the triangle

$\large\implies{\sf }$ Angle ( ACB+ ABC + CAB) = 180°

$\large\implies{\sf }$ Angle ( 90° + 48° + CAB) = 180°

$\large\implies{\sf }$ Angle ( 138° + CAB ) =180°

$\large\implies{\sf }$Angle CAB = (180° – 138° )

$\large\implies{\sf }$Angle CAB = 42°