Question

can any one solve sin(x+10)=cos(3x-68)?​

Answer 1

Step-by-step explanation:

answer is in the above picture

Answer 2

Step-by-step explanation:

$\sin(x + 10) = \cos(3x - 68) \\ \sin( \alpha ) = \cos(90 - \alpha ) \\ \cos(90 - (x + 10)) = \cos(3x - 68)$

now by comparing angles :

$80 - x = 3x - 68 \\ 148 = 4x \\ x = 37$