Math, asked by riturockstar, 9 months ago

can any one solve these​

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Answered by hurrey231
0

(1) (-3/5+4/9)+(-1/3) = (-3/5)+(4/9+(+1/3))

solution= (-27+20/45)+(-1/3) = (-3/5)+(12-9/9)

Here, 45 is the LCM of 5 and 9 = 9 is the LCM of 9 and 3

after solving the bracket of both sides we get

-7/45 + (-1/3) = (-3/5) +3/27 ( solve the bracket)

-7/45-1/3 = -3/5+3/9

-7-15/45 = -27+5/45

-22/45 = -22/45

So, RHS = LHS

(2). (-7/4)+{3/5+(-2/7)} = {(-7/4) +3/5} +(-2/7)

solution= (-7/4) + {21 - 10/35} = {-35+12/20} + (-2/7)

Here, 35 is the LCM of 5 and 7 = 20 is the LCM of 4 and 5

after solving the bracket we get

(-7/4) +11/35 = -23/20+(-2/7). ( solve the bracket)

-7/4+11/35 = -23/20-2/7

-35+44/140 = -161-40/140( 140 is the LCM of 35 and 4 = 140 is the LCM of 20 and 7)

9/140 is not equal to -201/140

So, RHS is not equal to LHS

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