can any one solve this
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sec² A - tan² A =1
(sec A - tan A)(sec + tan A)=1
( sec A+ tanA )=b/a
we have
(sec A - tan A)=a/b
subtract the equation
sec A-tan A-sec A-tan A= a/b-b/a
-2 tan A= a²-b²/ab
tan A= b²-a²/2ab
(sec A - tan A)(sec + tan A)=1
( sec A+ tanA )=b/a
we have
(sec A - tan A)=a/b
subtract the equation
sec A-tan A-sec A-tan A= a/b-b/a
-2 tan A= a²-b²/ab
tan A= b²-a²/2ab
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