Chemistry, asked by Anushkaaa1, 1 year ago

can any one solve this pro draw Neo pentane

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Answered by yadavbhavin290p9j6mi
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The chromium phenylcarbyne complexes (η5-C5R5)(CO)2Cr≡CPh (2a: R = H; 2b: R = Me) have been prepared and their structure, cyclic voltammetry and reactions with PMe3 are reported. The compounds 2a and 2b are obtained as red and purple thennolabile solids respectively after treatment of cis-Br(CO)2(pic)2Cr≡CPh (pic = 4-methylpyridine) (1) with NaCp (Cp ≡ C5H5) and KCp* (Cp* = C5Me5) respectively. Complex 2a adds PMe3 at the carbyne-carbon atom to give the green α-phosphoniocarhene complex Cp(CO)2Cr=C(PMe3)Ph (3), whereas 2b undergoes with PMe3 a carbyne—carbonyl coupling reaction to afford the green η2 ketenyl complex Cp* (CO)(PMe3)Cr[C(Ph) CO](4). Cyclic voltammetry studies show the phenylcarbyne complexes 2a and 2b and the carbene complex 3 to undergo a reversible one-electron oxidation in CH2Cl2 at E1/2 = 0.39 V, E1/2 = 0.20 V and E1/2 = −0.52 V respectively (potentials vs. the ferrocene/ferrocenium redox couple). In comparison, the ketenyl complex 4 is electrochemically inactive in the potential range of −1.5 to 1.0 V. The crystal structures of 2a and 3 are reported.
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