can any one solve this question please <br /><br />if any one post irrrelavent answer <br /><br />i will not forgive it
Answers
Answer:
a) V₀ = 13.5m/s
a) V₀ = 13.5m/sb) a = 2.1 m/s²
Explanation:-
1) Convert velocities to m/s
i) 20 km/h × 1000m/kg × 1h/3600s = 5.556m/s
ii) 40km/h = 11.111m/s
2) Red car, time elapsed to reach position x = 44.5m
Constant velocity ⇒ x = V×t ⇒ t = x / V
⇒ t₁ = 44.5m / 5.556m/s = 8s
3) Red car, time elapsed to reach position x = 77.6m
t₂ = 76.6m / 11.111/s = 6.9s
4) Green car, distance run at t₁ = 8s, x = 44.5m
i) uniform acceleration equation d = V₀t + at² / 2
ii) d = 220m - x = 220m - 44.5m = 175.5m = V₀ (8) + a (8)² /2
175.5 = 8V₀ + 32a ↔ equation (1)
5) Green car, distance run at t₂ = 6.9s, x = 76.6m
i) d = 220m - x = 220m - 76.6m = 143.4
ii) 143.4 = V₀t₂ + at₂² / 2
143.4 = V₀ (6.9) + a(6.9)² / 2
143.4 = 6.9V₀ + 23.8a ↔ equation (2)
6) Solve the system of equations:
175.5 = 8V₀ + 32a ↔ equation (1)
143.4 = 6.9V₀ + 23.8a ↔ equation (2)
V₀ = 13.5m/s
a = 2.1 m/s²