Math, asked by kommakoila, 1 year ago

can any one solve this sum?
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The dimensions of an open box are 50cm, 40cm and 23 cm. Its thickness is 3 cm. If 1 cubic cmof metal used in the box weight 0.5 gms, find the weight of the box.

Answers

Answered by siddhartharao77
2

Outer Dimensions:

Given, length of box = 50 cm.

Given, breadth of box = 40 cm.

Given, height of box = 23 cm.

We know that Volume of box = l * b * h.

⇒ 50 * 40 * 23

⇒ 46000 cm^3.


Inner Dimensions:

Given thickness of the box = 3 cm.

Length of the box = Outer length - Twice the width

                              = 50 - (2 * 3)

                              = 44 cm.


Breadth of the box = Outer Breadth - Twice the width

                               = 40 - (2 * 3)

                                = 34.


Height of the box = (23 - 3) {It is an open box}

                             = 20 cm.


We know that Volume of the box = L * b * h

⇒ 44 * 34 * 20

⇒ 29920.


Hence, Volume of the metal used in the box = Outer volume - Inner volume

⇒ 46000 - 29920

⇒ 16080 cm^3.


Now,

Weight of the metal = (16080 * 0.5)/1000

⇒ 8.04 kg.



Therefore, weight of the box = 8.04 kg.



Hope it helps!


siddhartharao77: :-)
kommakoila: inner dimensions?
kommakoila: pls explain how you calculated inner dimesions
kommakoila: understood.... thank you. :)
siddhartharao77: Done..do check now..Thanks
kommakoila: perfect ... thank you
siddhartharao77: Welcome
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