Question

can any one tell me derivation of trignomertry formulae

$sin ^{2} \alpha + cos ^{2} \alpha = 1$

Answer 1

Heya mate,

Proof ==>

$sin \alpha = \frac{p}{h} \\ cos \alpha = \frac{b}{h} \\ now \\ {sin}^{2} \alpha + {cos}^{2} \alpha = \: \frac{ {p}^{2} }{ {h}^{2} } + \frac{ {b}^{2} }{ {h}^{2} } \\ = = = > \frac{ {h}^{2} }{ {h}^{2} } \\ = = > 1 \\ \\ hence \: \: proved.$
#KEVIN
Hope it will help you...

Note==> i answered what i know, it may be wrong.