can any person give me answer
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COS2A =2COS²X-1
=BY OPEN IT
LIKE 1=SIN²X+COS²X
THE PUT THE VALUE OF 1
=2COS²X-SIN²X-COS²X
=COS²X-SIN²X
=BY OPEN IT
LIKE 1=SIN²X+COS²X
THE PUT THE VALUE OF 1
=2COS²X-SIN²X-COS²X
=COS²X-SIN²X
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by the trigonometric identities i.e
cos(a+b) =cos (a) *cos(b) - sin(a) *sin(b)
cos(2a) = cos(a+a)= cos (a) *cos(a) - sin (a) *sin(a) = cos²(a) - sin²(a)
hope it helps and would u mark me brainiest
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