Question

can any solve this problem for me

Answer 1

By Pythagoras Theorem,

AC = √(AB² - BC²)

=> AC = √(20² - 12²)

=> AC = √(400 - 144)

=> AC = √256

=> AC = 16

Sin∅ = P/H

=> sin angle ABC = 16/20

=> sin ABC = 4/5

Answer :- 4/5


Second :-

tan(x) = P/B

=> tan(x) = 12/9

=> tan (x) = 4/3

Again, by Pythagoras Theorem,

DB = √(9² + 12²)

=> DB = √(81 + 144)

=> DB = √225

=> DB = 15

so cos x = B/H

= cos x = 9/15

=> cos x = 3/5

sin x = P/H

=> sin x = 12/15

=> sin x = 4/5

So tan x - cos x + 3sin x

= 4/3 - 3/5 + 3 × 4/5

=> 4/3 - 3/5 + 12/5

=> 20/15 - 9/15 + 36/15

=> 11/15 + 36/15

=> 47/15

Answer 2

Hope that my first answer helps you a lot.



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