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le ho gaya dude
keep it
keep it
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IN Triangle CBD and triangle BCE, BD=CE,(cgiven) Angle BDC=AngleCEB (each angle 90) and CB=CB ( common) Hence, Triangle CBD congruence Triangle BCE. Now, b) Angle DCB = EBC (by c. p. c. t) hence proved.
ayushkatiyar81:
hmm
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