Question

can anybody answer 4 th question in polynomials

Answer 1

Answer:

Given,

x-1 = 0

x = 1 => 1 is the zero of the polynomial.

Then, p(x) = ax²-3(a-1)x-1

=> a(1²) - 3a -1×1 -1

=> a-3a-2

=> -2a-2

-2a-2 = 0

a = 2/-2

a = -1....

Step-by-step explanation:

Hope it helps you...

Answer 2

Answer:

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