Question

can anybody answer this question

Answer 1

Hey here is your answer

Answer 2

$let \: {2}^{x} = {3}^{y} = {12}^{z} = a \\ by \: this : \\ 2 = {a}^{ \frac{1}{x} } \\ 3 = {a}^{ \frac{1}{y} } \\ 12 = {a}^{ \frac{1}{z} } \\ \: we \: know \: that \: 12 = 4 \times 3 = {2}^{2} \times 3 \\ we \: can \: also \: write \: this \: as : \\ {a}^{ \frac{1}{z} } = {a}^{ \frac{2 \times 1}{x} } \times {a}^{ \frac{1}{y} } \\ since \: {b}^{m} \times {b}^{n} = {b}^{m + n} \\ \\ {a}^{ \frac{1}{z} } = {a}^{ \frac{2}{x} \: + \frac{1}{y} } \\ since \: the \: base \: is \: same \\ \frac{1}{z} \: = \frac{2}{x} + \frac{1}{y} \\ q.e.d.$