can anybody do this??????
Answers
yes I can solve it
35 is the Answer
Explanation
Equation 1: 20 + 20 + 20 = 60 (Hen = 20)
Equation 2: 20 + 3 + 3 = 26 (Eggs = 3)
Equation 3: 3 + 6 + 6 = 15 (Bananas = 6; Note that there are 6 bananas in one set)
Equation 4: 20 + (3 x 5) = 35 (There are only 5 bananas in this set, so bananas = 5)
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yes I can do this!!
lemme explain now.
in first column, we have 3 hens. right?
let it be "x"
=> x + x + x = 60
=> x = 20
value of one hen is 20.
now in the second column, there is one hen and 2 plates with 3 eggs each.
let the plate with 3 eggs each be "y"
=> 20 + y + y = 26
=> 2y = 6
=> y = 3
value of one plate is 3
so we can say value of one egg is 1? yeah we can..
next, there's a plate of egg and half dozen bananas (2 bundle whatever I dunno it's same)
half dozen - 6
let the half dozen of bananas be "z"
=> 3 + z + z = 15
=> 2z = 12
=> z = 6
here also, we can say value of 1 banana is 1..
now in the last column, there's one hen, 4 eggs and 4 bananas.
using bodmas method we get,
= 20 + (4 × 4)
= 20 + 16
= 36
I hope u understood..