Math, asked by shashankavsthi, 1 year ago

Can anybody explain me how to make graph of cosy=sinx.

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bmk2437: sorry i don't know the answer
shashankavsthi: okay no problem dear
rohirestle: Actually srry for msg if u find my ans really useful just go ahead no need of plenty of thx
shashankavsthi: he..he.. okay fine,from next time i willl.

Answers

Answered by yuvrajkj
3
put x=0 calculate y. then y=0 and calculate x. similarly put some genuine values of x & y and then plot them.

shashankavsthi: have you think about general solution concept?
shashankavsthi: btw thanks but we can't plot like u suggested!
yuvrajkj: general solution means nπ +- theta
bmk2437: can't understand the question . actually i don't know it .sorry
shashankavsthi: are u asking or telling
yuvrajkj: i think that is used in complex numbers
yuvrajkj: i am telling
shashankavsthi: i know it's answer and i have graph too but according to ur method we can't reach anywhere
bmk2437: ok thanks . coming to understand a little
Anonymous: y=cos^-1(sinx)=(π÷2)-sin^-1(sinx)=π÷2 - x,plot this, you will get the graph.
Answered by Anonymous
1

Step-by-step explanation:

http://www.bing.com/search?mkt=en-in&pc=VIVBD&form=VIVOBD&q=explain+me+how+to+make+graph+of+cosy%3Dsinx.#CA!EHAVC?ccid=ehacc_3&ecid=ehaec_3&eh=%3ciframe+width%3d%221280%22+height%3d%22720%22+src%3d%22%2f%2fwww.youtube.com%2fembed%2fFJEEMl0i-yg%3fautoplay%3d1%22+frameborder%3d%220%22+allowfullscreen%3e%3c%2fiframe%3e&PC=VIVBD

hope it helps u

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