Math, asked by bharath200031, 1 year ago

can anybody get this solution I couldn't understand​

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Answered by Anonymous
1

Answer:

❤️Hey mate ❤️

Here is your answer :-

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My solution:

In the word INVOLUTE, there are 4 vowels, namely, I,O,E,U and 4 consonants, namely, N, V, L and T.

The number of ways of selecting 3 vowels out of 4=C(4,3)=4. The number of ways of selecting 2 consonants out of 4=C(4,2)=6. Therefore, the number of combinations of 3 vowels and 2 consonants is 4+6=10.

Now, each of these 10 combinations has 5 letters which can be arranged among themselves in 5! ways. Therefore, the required number of different words is 10×5!=1200.

But the answer is 2880.

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Hope this will help you

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