can anybody get this solution I couldn't understand
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❤️Hey mate ❤️
Here is your answer :-
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My solution:
In the word INVOLUTE, there are 4 vowels, namely, I,O,E,U and 4 consonants, namely, N, V, L and T.
The number of ways of selecting 3 vowels out of 4=C(4,3)=4. The number of ways of selecting 2 consonants out of 4=C(4,2)=6. Therefore, the number of combinations of 3 vowels and 2 consonants is 4+6=10.
Now, each of these 10 combinations has 5 letters which can be arranged among themselves in 5! ways. Therefore, the required number of different words is 10×5!=1200.
But the answer is 2880.
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Hope this will help you
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