Question

Can anybody give its answer with explanation​

Answer 1

Answer:

x = 180-(70+40) = 180-110 = 70°

x = 70°

Answer 2

Answer:

A straight line angle = $180^{o}$

Given: ACB is a straight line

          ACD = $70^{o}$

          BCE = $40^{o}$

          DCE = x

To find: x

Solution:

∠ACD + ∠x + ∠BCE = $180^{o}$

$70^{o}$ + x + $40^{o}$ = $180^{o}$

$110^{o}$ + x = $180^{o}$

x =  $180^{o}$ - $110^{o}$

x = $70^{o}$

Therefore, x = $70^{o}$