Question

can anybody help in this que​

Answer 1

Step-by-step explanation:

$log_{e}( \frac{a + b}{2} ) = \frac{1}{2} \times ( log_{e}(a) + log_{e}(b) ) \\ = > log_{e}( \frac{a + b}{2} ) = \frac{1}{2} \times ( log_{e}(ab) ) \\ = > log_{e}( \frac{a + b}{2} ) = log_{e}( {ab}^{ \frac{1}{2} } ) = > log_{e}( \frac{a + b}{2} ) = log_{e}( \sqrt{ab} ) \\ = > both \: log \: have \: same \: base \: so \: compare \: the \: values \\ = > \frac{a + b}{2} = \sqrt{ab} \\ = > a + b =2 \sqrt{ab}$