Question

can anybody help in this question
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Answer 1

Answer:

a)

$\sqrt{ \frac{1 + x {}^{2} }{2 + x {}^{2} } }$

Step-by-step explanation:

Let's consider the value of x as 0 and substitute it in the question then,

$= \sin( \cot^{-1}( \cos( \tan {}^{ - 1} (x) ) ) ) \\ = \sin( \cot^{-1}( \cos( \tan {}^{ - 1} (0) ) ) )$

$\\ = \sin( \cot^{-1}( \cos( 0 ) ) ) \\ = \sin( \cot^{-1}(1) ) \\ = \sin( \frac{\pi}{4} ) \\ = \frac{1}{ \sqrt{2} }$

now, substitute x=0 in the options given and you'll get the answer.

Hope this helped you