Can anybody help me out to solve this question..
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In triangle ABC BP/PC = AQ/ QC --------- 1
In triangle DBC BP/PC = DR/RC -------2 from 1 and 2 AQ/QC = DR/RC
therefore QR is parallel to AD.
In triangle DBC BP/PC = DR/RC -------2 from 1 and 2 AQ/QC = DR/RC
therefore QR is parallel to AD.
fernandesnuriel:
the answer is not being arranged properly after entering
BP/PC = DR/RC
it forms BPT
Aww OK thanks a lot...
wlc
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