Question

can anybody help me to do this problem please​

Answer 1

Answer:(p+4)(p+6)

Step-by-step explanation:

p

2

+10p+24

Factor the expression by grouping. First, the expression needs to be rewritten as p

2

+ap+bp+24. To find a and b, set up a system to be solved.

a+b=10

ab=1×24=24

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.

1,24

2,12

3,8

4,6

Calculate the sum for each pair.

1+24=25

2+12=14

3+8=11

4+6=10

The solution is the pair that gives sum 10.

a=4

b=6

Rewrite p

2

+10p+24 as (p

2

+4p)+(6p+24).

(p

2

+4p)+(6p+24)

Factor out p in the first and 6 in the second group.

p(p+4)+6(p+4)

Factor out common term p+4 by using distributive property.

(p+4)(p+6)