Math, asked by Ankit1234, 1 year ago

can anybody help me to solve this question its urgent for exam

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Answered by studygenie

(x+y+z)^2 = x^2+y^2+z^2+2(xy+yz+zx)
(1)^2= x^2+y^2+z^2-2
x^2+y^2+z^2=1+2=3
Here I found the value of x^2+y^2+z^2 bcoz I need it to find the answer

x^3+y^3+z^3-3xyz= (x+y+z)(x^2+y^2+z^2-(xy+yz+zx)
x^3+y^3+z^3=1×[3-(-1)]-3×-1 {substituting the values}
x^3+y^3+z^3=4+3=7

Ankit1234: i cant understand it

Ankit1234: find the value of x3+y3+z3

Ankit1234: please edit it

Ankit1234: please edit it otherwise i will delete answer

studygenie: x3+y3+z3 = 7

Ankit1234: can you send attach file

Ankit1234: it is very difficult to understand this

studygenie: attach file as in......?

studygenie: do u want me to show u how to do it through writing ?

Ankit1234: yes

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