can anybody plZz solve it
by the method of rationalize the denominator
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√3+√2
√3-√2
√3+√2×√3+√2
√3-√2×√3+√2
[√3+√2]^2
[√3]^2-[√2]^2
[3+√6+4]
[3-2]
[7+√6]
1
So the rationlising factor is √3+√2
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