Question

can anybody solve 57 and 58 ?

Answer 1

Answer:

kp of the given Reaction is

= 1/(1)*(1)^1/2 = 1

Now, for this reaction n = 1

∆G° = - nFE°

= -(1)*(96500)*(1.36-0.22)= -(96.5)(1.18) kJ/mol

= -110 kJ/mol

So, the useful work should be

+110 kJ/mol

Now,

I'm not sure about the name of the water gas reaction name but I'm pretty sure that is neither Dow's process nor is it Kjehald's process for sure, it's either a or B.

Hope this helps you !