Question

can anybody solve it .....................​

Answer 1

$\Large{\underline{\underline{\mathfrak{\red{\bf{Solution}}}}}}$

$\Large{\underline{\mathfrak{\orange{\bf{Given}}}}}$

• x² + y² = 25xy _______(1)

$\Large{\underline{\mathfrak{\orange{\bf{prove}}}}}$

• 2 log (x + y) = 3 log 3 + log x + log y

$\Large{\underline{\underline{\mathfrak{\red{\bf{Explanation}}}}}}$

Add 2xy in equ(1) of both side

➡ x² + y² + 2xy = 25xy + 2xy

➡ (x + y)² = 27xy_______(2)

Using Some Important formula

★ log (ab) = log a + log b

★ log a^a = a log a.

Then,take log of equ(2) in both side

➡ log (x+y)² = log (27xy)

➡2.log(x+y) = log 27 + log x + log y

➡2.log(x+y) = log 3³ + log x + log y

➡2.log(x+y) = 3 log 3 + log x + log y

That's proved.

________________

Answer 2

$\Large{\underline{\underline{\mathfrak{\red{\bf{Explanation}}}}}}</p><p> </p><p>$

Add 2xy in equ(1) of both side

➡ x² + y² + 2xy = 25xy + 2xy

➡ (x + y)² = 27xy_______(2)

$\tt{Using \: Some \: Important \: formula }$

★ log (ab) = log a + log b

★ log a^a = a log a.

Then,take log of equ(2) in both side

➡ log (x+y)² = log (27xy)

➡2.log(x+y) = log 27 + log x + log y

➡2.log(x+y) = log 3³ + log x + log y

➡2.log(x+y) = 3 log 3 + log x + log y

That's proved.

________________