Math, asked by sumitrasen152, 1 year ago

can anybody solve the equation Xcube - 1 = 0


mithunnk101: x^3 - 1=0
Since a^3-b^3 = (a-b)(a^2 + b^2 + ab);
x^3 -1 = (x-1)(1+x+x^2)
soln's of (1+x+ x^2):
x={-1+ (1-4)^1/2}/2 ; {-1- (1-4)^1/2}/2
also, sq rt of -1 is defined as IOTA, represented by i.
so, x = (-1+i(sqrt3)}/2 , (-1-i(sqrt3)}/2
the fir term is represented by omega, w
next term is omega sq, w^2
so, cube roots of 1 are: 1, w ,^2

Answers

Answered by sagar2k
1
the answer will be 1 W Wsquare in this W and Wsquare are complex...
Answered by atreyee261
1
the answer is in the photo...hope it helps
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