Math, asked by saluarch, 1 year ago

Can anybody solve this....
A B C
+A B C
+A B C
__________
=B B B


What numbers are A B C ?

Mastermind can solve this...
Challenge!

Answers

Answered by lekhahasa
38
A=1,B=4,C=8
148+148+148=444

lekhahasa: please mark this as a brainliest
saluarch: Good
Answered by kvnmurty
62
    A B C 
  +A B C 
  +A B C
=======
    B B B 
======
so, we have   3 * C = B  or  3 C = 10 + B   or  3 C = 20 + B

1) 3 C = B
    then middle digits:  B+B+B = 3 B = 10+B  or 20+B
     =>  B = 5  or 10.   But B should be multiple of 3 as  3 C = B.
   so this is not possible.

2)  3 C = 10 + B
     then middle digits: 3 B + 1 = 10 + B    or  20 + B
           then   B is a fraction. so it is not right.

3)  3 C = 20 + B
        middle digits:   3 B + 2 = 10 + B  or  20 + B
              so B = 4  or  10     so,  B = 4.
        then  C = 20+4 / 3  = 8
        then   the carry to the hundreds place = 1.
        So  3 A + 1 = B    =>  A = 1
        
so the number is  1 4 8.


kvnmurty: logically the answer can be deduced... select as brainliest. click on red box: THANKS above please
saluarch: Good work....
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