can anybody solve this
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3. In ΔBOC and ΔDOC BO = DO [In a rhombus diagonals bisect each other] CO = CO Common BC = CD [All sides of a rhombus are equal] By using SSS Congruency, ΔBOC≅ΔDOC.
4.AD=BC
AB=DC
AC=AC(common)
By SSS congruence
triangleADC congruent to TriangleACB
AB||DC
DB=DB (COMMON)
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