Question

Can anybody solve this.
let p= tan A+ sec A. Then find the value of p+1/p
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Answer 1

$p = \tan \alpha + \sec\alpha \\ { \sec } ^{2} \alpha - { \tan }^{2} \alpha = 1 \\ ( \sec \alpha + \tan \alpha )( \sec \alpha - \tan \alpha ) = 1 \\ p( \sec \alpha - \tan \alpha ) = 1 \\ \sec \alpha - \tan \alpha = \frac{1}{p} \\ \\ p + \frac{1}{p} = \sec \alpha + \tan \alpha + \sec \alpha - \tan \alpha \\ = 2 \sec \alpha$