Question

Can. anybody solve this plz it's urgent....

Answer 1

Given np3 : np2 = 3:1

$= \ \textgreater \ \frac{n!}{n - 3!} * \frac{n - 2!}{2!} = \frac{3}{1}$

$= \ \textgreater \ \frac{(n - 2)!}{(n - 3)!} = 3$

$= \ \textgreater \ \frac{(n - 2)(n - 3)!}{(n - 3)!} = 3$

$= \ \textgreater \ (n - 2) = 3$

= > n = 3 + 2

= > n = 5.


Hope this helps!