can anybody teach me class 10 trigonometry ex:8.4 5th question 5th and 6th sub division by step by step please see my attachment
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Solution:
LHS = √(1+sinA)/(1-sinA)
= √[(1+sinA)(1+sinA)/(1-sinA)(1+sinA)]
= √[(1+sinA)²/(1²-sin²A)]
/* (a+b)(a-b) = a²-b² */
= √[(1+sinA)²/cos²A]
/* 1-sin²A = cos²A */
= (1+sinA)/cosA
= (1/cosA) + (sinA/cosA)
= secA+tanA
= RHS
••••
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