Math, asked by vasanth005, 11 months ago

can anybody teach me class 10 trigonometry ex:8.4 5th question 5th and 6th sub division by step by step please see my attachment​

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Answers

Answered by mysticd
2

Solution:

LHS = √(1+sinA)/(1-sinA)

= √[(1+sinA)(1+sinA)/(1-sinA)(1+sinA)]

= √[(1+sinA)²/(1²-sin²A)]

/* (a+b)(a-b) = a²-b² */

= √[(1+sinA)²/cos²A]

/* 1-sin²A = cos²A */

= (1+sinA)/cosA

= (1/cosA) + (sinA/cosA)

= secA+tanA

= RHS

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